Apyuxjj.176 net.math utzoo!decvax!harpo!eagle!mhuxt!pyuxjj!rlr Wed May 5 12:11:50 1982 Re: Solution(?) to oldie but goodie sqrt(-1) = i sqrt(1) = 1 sqrt(1/-1) = sqrt(-1) = i sqrt(1)/sqrt(-1) = 1/i 1/i = i (????????) OR i**2 = 1 (??????) I guess sqrt(a/b) != sqrt(a)/sqrt(b) where imaginaries are concerned. (Did I do that right?) Could someone explain. Rich Rosen pyuxjj!rlr ----------------------------------------------------------------- gopher://quux.org/ conversion by John Goerzen of http://communication.ucsd.edu/A-News/ This Usenet Oldnews Archive article may be copied and distributed freely, provided: 1. There is no money collected for the text(s) of the articles. 2. The following notice remains appended to each copy: The Usenet Oldnews Archive: Compilation Copyright (C) 1981, 1996 Bruce Jones, Henry Spencer, David Wiseman.